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Se os pontos estão alinhados, devemos ter
![\left[\begin{array}{ccc}2&5&1\\0&1&1\\1&m&1\end{array}\right] = 2(1-m)-5(-1)+1(-1) = 6-2m\\\\\\
fazendo -2m+6=0\\\\
-2m+6 = 0 \Rightarrow -2m = -6\\\\
\frac{-2m}{-2} = \frac{-6}{-2} \Rightarrow m = 3](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26amp%3B5%26amp%3B1%5C%5C0%26amp%3B1%26amp%3B1%5C%5C1%26amp%3Bm%26amp%3B1%5Cend%7Barray%7D%5Cright%5D++%3D+2%281-m%29-5%28-1%29%2B1%28-1%29+%3D+6-2m%5C%5C%5C%5C%5C%5C%0Afazendo+-2m%2B6%3D0%5C%5C%5C%5C%0A-2m%2B6+%3D+0+%5CRightarrow+-2m+%3D+-6%5C%5C%5C%5C%0A+%5Cfrac%7B-2m%7D%7B-2%7D+%3D+%5Cfrac%7B-6%7D%7B-2%7D+%5CRightarrow+m+%3D+3+ "\left[\begin{array}{ccc}2&5&1\\0&1&1\\1&m&1\end{array}\right] = 2(1-m)-5(-1)+1(-1) = 6-2m\\\\\\
fazendo -2m+6=0\\\\
-2m+6 = 0 \Rightarrow -2m = -6\\\\
\frac{-2m}{-2} = \frac{-6}{-2} \Rightarrow m = 3")
Logo, m = 3.
Logo, m = 3.
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