Question

qm soube pfvr responde aiii e pra hoje. resolver são raízes (2x+3)*-9=12x *quadrada

Answer 1

Assim o (2x+3)ao quadrado -9=12x

(2x + 3)² - 9 = 12x
(2x + 3)(2x + 3) - 9 = 12x
(4x² + 6x + 6x + 9) - 9 = 12x 
(4x² + 12x + 9) - 9 = 12x
4x² + 12x + 9 - 9 = 12x
4x² + 12x      0    = 12x

4x² + 12x = 12x   ( igualar a zero)  olha o SINAL
4x² + 12x - 12x = 0
4X²         0        = 0

4x² = 0
x² = 0/4
x² = 0

x = + - 0

assim
x' e x" = 0