• Matéria: Matemática
  • Autor: H7tedvarest8haintist
  • Perguntado 9 anos atrás

Determine f(0), f(1), f(2), f(3), f(4), e f(-1) das seguintes funções :A) f (x) = 2x+4B) f (x) = 3x+1C) f (x) = -2x+2C) f (x) = x-4E) f (x) = 3x-5

Respostas

respondido por: Mkse
68
Determine f(0), f(1), f(2), f(3), f(4), e f(-1) das seguintes funções :

A) f (x) = 2x+4
    f(0) = 2(0) + 4
    f(0) = 0 + 4
    f(0) = 4

f(x) = 2x + 4
f(1) = 2(1) + 4
f(1) = 2 + 4
f(1) = 6
f(x) = 2x + 4
f(2) = 2(2) + 4
f(2) = 4 + 4
f(2) = 8
f(x) = 2x + 4
f(3) = 2(3) + 4
f(3) = 6 + 4
f(3) = 10
f(x) = 2x + 4
f(4) = 2(4) + 4
f(4) = 8 + 4
f(4) = 12
f(x) = 2x + 4
f(-1) = 2(-1) + 4
f(-1) = - 2 + 4
f(-1) = 2

B) f (x) = 3x+1
    f(0) = 3(0) + 1
    f(0) = 0 + 1
    f(0)  = 1
f(x) = 3x + 1
f(1) = 3(1) + 1
f(1) = 3 + 1
f(1) = 4
f(x) = 3x + 1
f(2) = 3(2) + 1
f(2) = 6 + 1
f(2) = 7
f(x) = 3x + 1
f(3) = 3(3) + 1
f(3) = 9 + 1
f(3) = 10
f(x) = 3x + 1
f(4) = 3(4) + 1
f(4) = 12 + 1
f(4) = 13
f(x) = 3x + 1
f(-1) = 3(-1) + 1
f(-1) = - 3 + 1
f(-1) = - 2
 
C) f (x) = -2x+2
f(0) = - 2(0) + 2
f(0) = - 0 + 2
f(0) = 2
f(x)  = - 2x + 2
f(1) =  - 2(1) + 2
f(1) = - 2 + 2
f( 1) = 0
f(x) = - 2x + 2
f(2) = - 2(2) + 2
f(2) = - 4 + 2
f(2) = - 2
f(x) = - 2x + 2
f(3) = - 2(3) + 2
f(3) = - 6 + 2
f(3) = - 4
f(x) = - 2x + 2
f(4) = - 2(4) + 2
f(4) = - 8 + 2
f(4) = - 6
f(x) = -2x + 2
f(-1) = - 2(-1) + 2
f(-1) = + 2 + 2
f(-1) = 4
 
C) f (x) = x-4
f(0) = 0 - 4
f(0) = - 4
f(x)=  x - 4
f(1) = 1 - 4
f(1) = - 3
f(x) = x - 4
f(2) = 2 - 4
f(2) = - 2
f(x) =  x - 4
f3) = 3 - 4
f(3) = - 1
f(x) = x - 4
f(4) = 4 - 4
f(4) = 0
 
E) f (x) = 3x-5
f(0) = 3(0) - 5
f(0) = 0 - 5
f(0) = - 5
f(x) = 3x - 5
f(1) = 3(1) - 5
f(1) = 3 - 5
f(1) = - 2
f(x) = 3x - 5
f(2) = 3(2) - 5
f(2) = 6 - 5
f(2) = 1
f(x) = 3x - 5
f(3) = 3(3) - 5
f(3) = 9 - 5
f(3) = 4
f(x) = 3x - 5
f(4) = 3(4) - 5
f(4) = 12 - 5
f(4) = 7
f(x) = 3x - 5
f(-1) = 3(-1) - 5
f(-1) = - 3 - 5
f(-1) = - 8

respondido por: jm6987150
10

Resposta:

f(1),f(3),f(-4),f(-0)

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