Question

Resolva a integral indefinida

Answer 1

Oi 

∫ (x + 1)/√x dx

u = √x, du = 1/2√x dx 

∫ (x + 1)/√x dx = 2 ∫ (u² + 1) du = 2 ( ∫ u² du + ∫ 1 du

2 * ( u³/3 + u ) = 2u³/3 + 2u  

u = √x

∫ (x + 1)/√x dx = 2√x*(x + 3)/3 + C 

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