Question

to com bastante duvidas pra fazer essa folha me ajudem ai glr

Answer 1

AB= BC= considerando  como  x 


AB/BC= DE/EG
X/X= 5/EG
1=5/EG
EG= 5

*como o triangulo EFG é equilátero ,EG= FG

RESP: alternativa [c]
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2- resp: alternativa[d]
resolução ver anexo
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3- calculando x---->FB/FC= BA/CD
                                24/42= X/70
                                4/7=X/70
                               X= 4/7:1/70
                               X=4/7*70/1
                               X= 40

calculando y-------->FA/FD=FB/FC
                                32/32+Y=24/42
                                32/32+Y= 4/7
                                4*(32+Y)=7*32
                                128+4Y=224
                                4Y=224-128
                                Y=96/4
                                Y= 24
LOGO x= 40   y=24

resp: alternativa [d]
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4)CD/AB=CE/AE
   50/136= 75/AE
   50*AE= 136*75
   AE=10.200/50
   AE=204

resp: alternativa [c]
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5) EC/AB= CD/AD
    EC/15= 4/12
    EC=4/12 :1/15
    EC= 4/12*15/1
    EC=60/12
    EC= 5

resp: alternativa [d]
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6-) resp: alternativa[a]
resolução ver anexo
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7) resp: alternativa [a]
resolução ver anexo
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8-)