• Matéria: Matemática
  • Autor: Issam1969
  • Perguntado 9 anos atrás

O é o quociente de 8+i/2-i é igual a:

Respostas

respondido por: Anônimo
3
Boa tarde!

Solução!

\left \dfrac{8+i}{2-i} \right \\\\\\\
\left ( \dfrac{8+i}{2-i} \times \dfrac{2+i}{2+i}  \right )\\\\\\\
\left ( \dfrac{16+8i+2i+i ^{2}}{4+2i-2i-i^{2} }  \right )\\\\\\\
\left ( \dfrac{16+10i+i ^{2}}{4-i^{2} }  \right )\\\\\\\
Lembrado:i^{2}=-1~~substituindo!\\\\\\\ 
\left ( \dfrac{16+10i-1}{4-(-1)}  \right )\\\\\\\

\left ( \dfrac{16+10i-1}{4+1}  \right )\\\\\\\
\left ( \dfrac{16-1+10i}{5}  \right )\\\\\\\
\left ( \dfrac{15+10i}{5}  \right )\\\\\\\
\left ( \dfrac{5(3+2i)}{5}  \right )\\\\\\\

3+2i\\\\\\
\boxed {Resposta:3+2i }

Boa tarde!

Bons estudos!

Issam1969: Obrigado !!
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