Question

resolva essa conta de bhaskara

Answer 1

-x²-4x+12=0     ===> a=-1, b=-4, c=12

Δ= b²-4ac
Δ= (-4)²-4*(-1)*12
Δ= 16 + 48
Δ= 64

x= -b+-√Δ / 2a       ===>√Δ= √64=8

x₁= -(-4)+8 / 2*(-1)
x₁= 12 / -2
x₁= -6

x₂= -(-4)-8 / 2*(-1)
x₂= -4 / -2
x₂= 2

Raízes: -6 e 2