Question

a)log de 32 na base 2=x
b)log de 27 na base x=3
c)log de x na base 5=2
d)log de 9 na base 9=x

Answer 1

a) log2^32  = x

log2^x = 32
log2^x = 2^5
logo, x = 5
b) logx^27 = 3
logx³ = 27

x = ∛27
x = 3

c) log5^x = 2
log5² = x

d) x = 25
log9^9 = x
log9^x = 9

x = 1