Question

Calcular o 7º termo do desenvolvimento de $( \frac{a}{ \sqrt{b} }+ \frac{ \sqrt{b} }{a} )^{10}$

Answer 1

$T_7 = \binom{10}{6}( \frac{ \sqrt{b} }{a} )^6 \,( \frac{a}{ \sqrt{b} } )^4\,(-1)^6\\\\ T_7 = +210 \frac{ \sqrt{b^6} }{a^3} \cdot \frac{a^4}{ \sqrt{b^4} } \\\\ T_7 = 210 \frac{a^4b^2}{a^6b^2} = \frac{210b}{a^2}$