Respostas
respondido por:
2
x²-2x=2x+12
x²-2x-2x-12=0
x²-4x-12=0
(-4)²-4.1.(-12)
16+48=64
-(-4_+-raiz64/2.1
4+-8/2
X1= 4+8/2> 12/2= 6
X2= 4-8/2> -4/2 = -2
x²-2x-2x-12=0
x²-4x-12=0
(-4)²-4.1.(-12)
16+48=64
-(-4_+-raiz64/2.1
4+-8/2
X1= 4+8/2> 12/2= 6
X2= 4-8/2> -4/2 = -2
respondido por:
1
x²-2x=2x+12
x²-2x-2x-12=0
x²-4x-12=0
∆=b²-4ac
∆=(-4)² -4.1.(-12)
∆= 16+48=64
√∆ =8
x=-b±√∆)/2a
x = -(-4)±8/2
x'=4+8/2
x'12/2=6
x''/ =4-8/2
x''=-4/2=-2
x²-2x-2x-12=0
x²-4x-12=0
∆=b²-4ac
∆=(-4)² -4.1.(-12)
∆= 16+48=64
√∆ =8
x=-b±√∆)/2a
x = -(-4)±8/2
x'=4+8/2
x'12/2=6
x''/ =4-8/2
x''=-4/2=-2
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