Respostas
respondido por:
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Boa noite!
Solução!
![a1=6\\\\
a2=x\\\\\
a3=54\\\\\\\
\dfrac{a2}{a1}= \dfrac{a3}{a2}\\\\\\\\
\dfrac{x}{6}= \dfrac{54}{x}\\\\\\\\
x^{2} =324\\\\
x= \sqrt{324}\\\\\
x=\pm18](https://tex.z-dn.net/?f=a1%3D6%5C%5C%5C%5C%0Aa2%3Dx%5C%5C%5C%5C%5C%0Aa3%3D54%5C%5C%5C%5C%5C%5C%5C%0A+%5Cdfrac%7Ba2%7D%7Ba1%7D%3D+%5Cdfrac%7Ba3%7D%7Ba2%7D%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cdfrac%7Bx%7D%7B6%7D%3D+%5Cdfrac%7B54%7D%7Bx%7D%5C%5C%5C%5C%5C%5C%5C%5C%0A%0A+x%5E%7B2%7D+%3D324%5C%5C%5C%5C%0Ax%3D+%5Csqrt%7B324%7D%5C%5C%5C%5C%5C%0Ax%3D%5Cpm18+%0A++ "a1=6\\\\
a2=x\\\\\
a3=54\\\\\\\
\dfrac{a2}{a1}= \dfrac{a3}{a2}\\\\\\\\
\dfrac{x}{6}= \dfrac{54}{x}\\\\\\\\
x^{2} =324\\\\
x= \sqrt{324}\\\\\
x=\pm18")
![Resposta!\\\\\
Para~~x=18~~temos~~uma~~P.G~~crescente.\\\\\\
Para~~x=-18~~temos~~uma~~P.G~~Alternante](https://tex.z-dn.net/?f=Resposta%21%5C%5C%5C%5C%5C%0A%0A%0APara%7E%7Ex%3D18%7E%7Etemos%7E%7Euma%7E%7EP.G%7E%7Ecrescente.%5C%5C%5C%5C%5C%5C%0APara%7E%7Ex%3D-18%7E%7Etemos%7E%7Euma%7E%7EP.G%7E%7EAlternante "Resposta!\\\\\
Para~~x=18~~temos~~uma~~P.G~~crescente.\\\\\\
Para~~x=-18~~temos~~uma~~P.G~~Alternante")
Boa noite!
Bons estudos!
Solução!
Boa noite!
Bons estudos!
respondido por:
0
Se (6,x,54) é uma PG entâo x²=6·54⇒x²=324⇒x=+-18 e temos
(6,-18,54) e PG de razão q=-3 e (6,18,54) é PG de razão q = 3
(6,-18,54) e PG de razão q=-3 e (6,18,54) é PG de razão q = 3
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