Question

Calcule x sabendo que o ponto P(x,1) equidista dos pontos
A(2,3) e B(3,-1).

Answer 1

$d_{PA} = d_{PB} \sqrt{(x-2) ^{2} } +(1-3) ^{2} = \sqrt{(x-3) ^{2} } + (1+1) ^{2} (x-2)^{2}+(1-3)^2 =(x-3)^2+(1+1)^2 x^2-4x +4+4 + x^2-6x+9+4 -x4 + 4 = -6x+9 -x4 + 6x=9 - 4 2x = 5 x = \frac{5}{2}$