Question

quantos gramas de Ca(OH)2 sao necessario para neutralizar 50,00ml de 1,00 mol/l de HNO3

Answer 1

Ca(OH)2 + 2HNO3-------> Ca(NO3)2 + 2H2O

Ca(OH)2=74g/mol
HNO3=63g/mol

M=m/mmV(L)
1mol/L=m/63g/mol*0,05L
m=3,15g HNO3

2(63g)--------74g
3,15g---------X
X= 1,85g Ca(OH)2 para neutralizar esses 50mL de HNO3