Respostas
respondido por:
1
Segue os calculos em anexo, qualquer coisa lergunta :D
Anexos:
Anônimo:
Boa noite Leonardo! Desculpe tem uma raiz complexa.
respondido por:
1
Boa noite Nicolas!
Solução!
![\dfrac{(-2)^{2}+ \sqrt[3]{-8} }{\left ( \dfrac{7}{2}+log_{2}32\right )^{0} -log_{2}32}](https://tex.z-dn.net/?f=+%5Cdfrac%7B%28-2%29%5E%7B2%7D%2B+%5Csqrt%5B3%5D%7B-8%7D++%7D%7B%5Cleft+%28+%5Cdfrac%7B7%7D%7B2%7D%2Blog_%7B2%7D32%5Cright+%29%5E%7B0%7D+-log_%7B2%7D32%7D++%0A%0A%0A "\dfrac{(-2)^{2}+ \sqrt[3]{-8} }{\left ( \dfrac{7}{2}+log_{2}32\right )^{0} -log_{2}32}")
Vou fazer a raiz e o logaritmo separados,e em seguida substituir.
![\sqrt[3]{-8}= \sqrt[3]{-2^{3}}=-2\\\\\\\
log_{2}32\\\\\\
log_{2}32=x\\\\\\
2^{x}=2^{5} \\\\\
x=5\\\\\\
\boxed{ log_{2}32=5}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B-8%7D%3D+%5Csqrt%5B3%5D%7B-2%5E%7B3%7D%7D%3D-2%5C%5C%5C%5C%5C%5C%5C%0Alog_%7B2%7D32%5C%5C%5C%5C%5C%5C%0Alog_%7B2%7D32%3Dx%5C%5C%5C%5C%5C%5C%0A2%5E%7Bx%7D%3D2%5E%7B5%7D+%5C%5C%5C%5C%5C%0Ax%3D5%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7B+log_%7B2%7D32%3D5%7D "\sqrt[3]{-8}= \sqrt[3]{-2^{3}}=-2\\\\\\\
log_{2}32\\\\\\
log_{2}32=x\\\\\\
2^{x}=2^{5} \\\\\
x=5\\\\\\
\boxed{ log_{2}32=5}")
![\dfrac{(-2)^{2}+ \sqrt[3]{-8} }{\left ( \dfrac{7}{2}+log_{2}32\right )^{0} -log_{2}32}\\\\\\\\\\ \dfrac{4-2}{\left ( \dfrac{7}{2}+5\right )^{0} -5}\\\\\\\\\\\ Todo~~numero~~ elevado~~ a ~~zero~~ e~~ igual ~~a~~1\\\\\\\\ \dfrac{4-2}{( 1 -5)}\\\\\\\\\\\ \dfrac{2}{-4}\\\\\\\\\\\ -\dfrac{1}{2}\\\\\\\
\boxed{Resposta:- \dfrac{1}{2}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%28-2%29%5E%7B2%7D%2B+%5Csqrt%5B3%5D%7B-8%7D+%7D%7B%5Cleft+%28+%5Cdfrac%7B7%7D%7B2%7D%2Blog_%7B2%7D32%5Cright+%29%5E%7B0%7D+-log_%7B2%7D32%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C+%5Cdfrac%7B4-2%7D%7B%5Cleft+%28+%5Cdfrac%7B7%7D%7B2%7D%2B5%5Cright+%29%5E%7B0%7D+-5%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C+Todo%7E%7Enumero%7E%7E+elevado%7E%7E+a+%7E%7Ezero%7E%7E+e%7E%7E+igual+%7E%7Ea%7E%7E1%5C%5C%5C%5C%5C%5C%5C%5C+%5Cdfrac%7B4-2%7D%7B%28+1+-5%29%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C+%5Cdfrac%7B2%7D%7B-4%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C+-%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A-+%5Cdfrac%7B1%7D%7B2%7D%7D+++ "\dfrac{(-2)^{2}+ \sqrt[3]{-8} }{\left ( \dfrac{7}{2}+log_{2}32\right )^{0} -log_{2}32}\\\\\\\\\\ \dfrac{4-2}{\left ( \dfrac{7}{2}+5\right )^{0} -5}\\\\\\\\\\\ Todo~~numero~~ elevado~~ a ~~zero~~ e~~ igual ~~a~~1\\\\\\\\ \dfrac{4-2}{( 1 -5)}\\\\\\\\\\\ \dfrac{2}{-4}\\\\\\\\\\\ -\dfrac{1}{2}\\\\\\\
\boxed{Resposta:- \dfrac{1}{2}}")
Boa noite!
Bons estudos!
Solução!
Vou fazer a raiz e o logaritmo separados,e em seguida substituir.
Boa noite!
Bons estudos!
oi
poderia me informar de onde vei aquele ''i'' ?
I é da raiz cubica negativa. Raiz complexa! Já esta estudando?
Dá uma olhada na caixa de mensagens.
Cara raiz cubica de -8 é -2
Alias ele nao deixou claro o dominio
Confere direito,esta relacionado as raizes negativa!
Desculpe não estou querendo ser o dono do conhecimento,só uma dica.
Leonardo você esta correto!
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