Question

oi, a resposta é 2..obrigada

Answer 1

$\frac{( \sqrt{3}-1)^2+(1- \sqrt{3} )^2 }{2- \sqrt{3} } \\ \\ \frac{( \sqrt{3})^2+ (-2. \sqrt{3})+(-1)^2 +1^2+(-2. \sqrt{3})+(- \sqrt{3})^2 }{2- \sqrt{3} } \\ \\ \frac{3-2 \sqrt{3}+1+1-2 \sqrt{3}+3 }{2 -\sqrt{3} } \\ \\ \frac{8-4 \sqrt{3} }{2- \sqrt{3} } =4$