Question

Trigonometria : Alguém ?? Quanto vale tg π/18 + tg π/9 dividido por 1-tg π/18 . tg π;9 ?

Answer 1

Oi Dany

tg(a + b) = (tg(a) + tg(b))/(1 - tg(a)*tg(b))

tg(π/18 + π/9) = (tg(π/18) + tg(π/9)/(1 - tg(π/18)*tg(π/9))

tg(π/18 + π/9)  = tg(3π/18) = tg(π/6) = tg(30°) = √3/3