Respostas
respondido por:
105
Boa noite Rafaela!
Solução!
Para acharmos o número de termo de uma P.A vamos usar a formula do termo geral.
![an=3\\\\\\\
a1=2\\\\\\
r= \dfrac{1}{10} \\\\\\\\
an=a1+(n-1).r\\\\\\
3=2+(n-1). \frac{1}{10}\\\\\
3=2+ \frac{n}{10}- \frac{1}{10}\\\\\\\
30=20+n-1\\\\\\
30-20+1=n\\\\\
10+1=n\\\\
11=n\\\\\
\boxed{n=11}](https://tex.z-dn.net/?f=an%3D3%5C%5C%5C%5C%5C%5C%5C%0Aa1%3D2%5C%5C%5C%5C%5C%5C%0Ar%3D+%5Cdfrac%7B1%7D%7B10%7D+%5C%5C%5C%5C%5C%5C%5C%5C%0Aan%3Da1%2B%28n-1%29.r%5C%5C%5C%5C%5C%5C%0A3%3D2%2B%28n-1%29.+%5Cfrac%7B1%7D%7B10%7D%5C%5C%5C%5C%5C%0A3%3D2%2B+%5Cfrac%7Bn%7D%7B10%7D-+%5Cfrac%7B1%7D%7B10%7D%5C%5C%5C%5C%5C%5C%5C%0A30%3D20%2Bn-1%5C%5C%5C%5C%5C%5C%0A30-20%2B1%3Dn%5C%5C%5C%5C%5C%0A10%2B1%3Dn%5C%5C%5C%5C%0A11%3Dn%5C%5C%5C%5C%5C%0A%5Cboxed%7Bn%3D11%7D++ "an=3\\\\\\\
a1=2\\\\\\
r= \dfrac{1}{10} \\\\\\\\
an=a1+(n-1).r\\\\\\
3=2+(n-1). \frac{1}{10}\\\\\
3=2+ \frac{n}{10}- \frac{1}{10}\\\\\\\
30=20+n-1\\\\\\
30-20+1=n\\\\\
10+1=n\\\\
11=n\\\\\
\boxed{n=11}")
Boa noite!
Bons estudos!
Solução!
Para acharmos o número de termo de uma P.A vamos usar a formula do termo geral.
Boa noite!
Bons estudos!
respondido por:
42
an = a1+(n-1)r
3 = 2+(n-1)1/10
3 = 2 + n/10 - 1/10
30 = 20 + n - 1
n = 30 -20 +1
n = 11
3 = 2+(n-1)1/10
3 = 2 + n/10 - 1/10
30 = 20 + n - 1
n = 30 -20 +1
n = 11
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