Question

1-(x+2)^=0 qual é o resultado

Answer 1

1 - (x + 2)² = 0
1 - (x² + 2.2x + 4) = 0
1 - (x² + 4x + 4) = 0
1 - x² - 4x - 4 = 0
- x² - 4x - 4 + 1 = 0
-x² - 4x - 3 = 0 ( - 1)
x² + 4x + 3 = 0
a = 1; b = 4; c = 3

Δ = b² - 4ac
Δ = 4² - 4.1.3
Δ = 16 - 12
Δ = 4

x = - b +/- √Δ     = - 4 +/- √4
      ---------------     ---------------
             2a                  2.1

x = - 4 + 2
      ----------- = -2/2 = - 1
           2

x = - 4 - 2
      ---------- = - 6/2 = - 3
            2

R.: x = - 1 e x = - 3
 

Answer 2

$1-(x-2)^2=0\\ \\-(x-2)^2=0-1\\ \\-(x-2)^2=-1\ \ \ \ \times (-1)\\ \\(x-2)^2=1\\ \\x-2=\pm \sqrt{1} \\x-2=\pm 1 \\x'=1+2 \ \ \ \ \ \ \ \ \ \ x''=-1+2\\ \\x'=3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x''=1\\ S=\{ 1, \ 3\}$

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$1-(x-2)^2=0\\ 1 -(x^2-4x+4)=0\\ 1 -x^2+4x-4=0\\ -x^2+4x+1-4=0\\ -x^2+4x-3=0$