Question

Sendo A=2,B= 1 e C=3. A²-2B/3C +A/6 +3B

Answer 1

$A^2-\frac{2B}{3C}+\frac{A}{6}+3B\\ \\ 2^2-\frac{2.1}{3.3}+\frac{1}{6}+3.1=4-\frac{1}{3}+\frac{1}{6}+3=\frac{24-2+3+18}{6}=\frac{43}{6}$