Question

quais são as raízes da equações x2+5x+6=0

Answer 1

x2+5x+6=0
Δ=$b^{2} -4.a.c$
Δ=$5^{2}-4.1.6$
Δ=25-24
Δ=1
$x= \frac{-b \frac{+}{-} \sqrt{delta} }{2.a}$
$x= \frac{-5 \frac{+}{-} 1}{2}$
x'=$\frac{-5+1}{2}$
x'=$\frac{-4}{2}$
$x^{'} = -2$
$x^{"} = \frac{-5-1}{2}$
$x^{"} = \frac{-6}{2}$
$x^{"} = -3$
$\ S=(-2, -3)$

Answer 2

x²+5x+6=0  b²-4AC = 5²-4.1.6 =25-24 = 1
A- 1             ( -b+/-Raiz 1) / 2.A 
B- 5              X'= (-5-1) /2 = -6/2 = -3
C- 6             X''= (-5+1)/2 = -4/2 = -2