Question

resolva as equações irracionais √X+3=X-3

Answer 1

$\sqrt{x+3}=x-3 (\sqrt{x+3}) ^{2} = (x-3)^{2} x + 3 = x^{2}-6x+9 -x^{2}+6x-9+x+3=0 -x^{2}+7x-6=0$

Δ = b² - 4ac
Δ = 7² - 4(-1)(-6)
Δ = 49 - 24
Δ = 25
x' = (-b + √Δ)/2a                         x'' = (-b - √Δ)/2a
x' = (-7 + √25)/2(-1)                    x'' = (-7 - √25)/2(-1)
x' = (-7 + 5)/-2                            x'' = (-7 - 5)/-2
x' = -2/-2                                     x'' = -12/-2
x' = 1                                           x'' = 6

S = {1, 6}

Answer 2

Resposta:

=x−3

x+3

2

=(x−3)

2

x+3=x

2

−6x+9

−x

2

+x+6x+3−9=0

−x

2

+7x−6=0

a=−1,b=7,c=−6

Δ=b

2

−4ac

Δ=7

2

−4.(−1).(−6)

Δ=49−24

Δ=25

x=

2a

−b±

Δ

x=

2.(−1)

−7±

25

x=

−2

−7±5

x=

−2

−7+5

x=

−2

−2

=1

x=

−2

−7−5

x=

−2

−12

=6