Question

Calcule a integral indefinida

z) $\int\ {}(3x^2+5+ \sqrt{x} ) \, dx$

Answer 1

OI Lucas

∫ (3x² + 5 +  √x) dx = x³ + 5x + 2x*√x/3 + C

.

Answer 2

$\sf \displaystyle \int \left(3x^2+5+\sqrt{x}\right)dx\\\\\\=\int \:3x^2dx+\int \:5dx+\int \sqrt{x}dx\\\\\\=x^3+5x+\frac{2}{3}x^{\frac{3}{2}}\\\\\\\to \boxed{\sf =x^3+5x+\frac{2}{3}x^{\frac{3}{2}}+C}$