Question

1)considere a função definida por f(x)=$\frac{x}{2} +1$, calcule os valores numéricos:
a)f(0)
b)f(-1)
c)f(2)
d)f(4)
e)f(-6)

Answer 1

$f(x)= \frac{x}{2} +1 \\ \\ \\ a)f(0)= \frac{0}{2} +1=1 \\ \\ \\ b)f(-1)= \frac{-1}{2} +1 \\ \\ f(-1)= \frac{-1+1.2}{2} = \frac{-1+2}{2} = \frac{1}{2} \\ \\ \\ c) f(2)=\frac{2}{2} +1=1+1=2 \\ \\ \\ d)f(4)= \frac{4}{2} +1=2+1=3 \\ \\ \\e) f(-6)= \frac{-6}{2} +1=-3+1=-2$