Matrizes.
Se A = ( 1 -2 3 | 4 0 5 ) e B = ( 6 -1 -8 | 0 2 -1) determine:
a) 
A + 3B.
b) Calcule x e y considerando as matrizes A e B acima 
.
supevensie:
Olha, eu preciso que pelo menos a letra a seja resolvida, a b eu consigo fazer de boa.
Mas preciso da a pra conseguir fazer a b, ne.
amigo, as matrizes A e B têm duas linhas e três colunas ou três linhas e duas colunas?
duas linhas e três colunas
blz, já faço pra ti
muito obrigada
Está em boas mãos, não precisa pedir socorro kk
Respostas
respondido por:
1
Oi! Tá tudo bem contigo?
Façamos da seguinte forma:
![A= \left[\begin{array}{ccc}1&-2&3\\4&0&5\end{array}\right] \\ \\ \\ B=\left[\begin{array}{ccc}6&-1&-8\\0&2&-1\end{array}\right] \\ \\ \\](https://tex.z-dn.net/?f=A%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B-2%26amp%3B3%5C%5C4%26amp%3B0%26amp%3B5%5Cend%7Barray%7D%5Cright%5D++%5C%5C+%5C%5C+%5C%5C+B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26amp%3B-1%26amp%3B-8%5C%5C0%26amp%3B2%26amp%3B-1%5Cend%7Barray%7D%5Cright%5D++%5C%5C+%5C%5C+%5C%5C "A= \left[\begin{array}{ccc}1&-2&3\\4&0&5\end{array}\right] \\ \\ \\ B=\left[\begin{array}{ccc}6&-1&-8\\0&2&-1\end{array}\right] \\ \\ \\")
![\displaystyle -\frac{2}{3}A+3B= -\frac{2}{3}\left[\begin{array}{ccc}1&-2&3\\4&0&5\end{array}\right]+3\left[\begin{array}{ccc}6&-1&-8\\0&2&-1\end{array}\right] \\ \\ \\ =\left[\begin{array}{ccc}- \frac{2}{3} & \frac{4}{3} &-2\\ -\frac{8}{3} &0&- \frac{10}{3} \end{array}\right] + \left[\begin{array}{ccc}18&-3&-24\\0&6&-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle++-%5Cfrac%7B2%7D%7B3%7DA%2B3B%3D+-%5Cfrac%7B2%7D%7B3%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B-2%26amp%3B3%5C%5C4%26amp%3B0%26amp%3B5%5Cend%7Barray%7D%5Cright%5D%2B3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26amp%3B-1%26amp%3B-8%5C%5C0%26amp%3B2%26amp%3B-1%5Cend%7Barray%7D%5Cright%5D+%5C%5C+%5C%5C+%5C%5C+%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-+%5Cfrac%7B2%7D%7B3%7D+%26amp%3B+%5Cfrac%7B4%7D%7B3%7D+%26amp%3B-2%5C%5C+-%5Cfrac%7B8%7D%7B3%7D+%26amp%3B0%26amp%3B-+%5Cfrac%7B10%7D%7B3%7D+%5Cend%7Barray%7D%5Cright%5D+%2B+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D18%26amp%3B-3%26amp%3B-24%5C%5C0%26amp%3B6%26amp%3B-3%5Cend%7Barray%7D%5Cright%5D "\displaystyle -\frac{2}{3}A+3B= -\frac{2}{3}\left[\begin{array}{ccc}1&-2&3\\4&0&5\end{array}\right]+3\left[\begin{array}{ccc}6&-1&-8\\0&2&-1\end{array}\right] \\ \\ \\ =\left[\begin{array}{ccc}- \frac{2}{3} & \frac{4}{3} &-2\\ -\frac{8}{3} &0&- \frac{10}{3} \end{array}\right] + \left[\begin{array}{ccc}18&-3&-24\\0&6&-3\end{array}\right]")
![= \left[\begin{array}{ccc}- \frac{2}{3}+18 & \frac{4}{3}-3 &-2-24\\ -\frac{8}{3}+0 &0+6&- \frac{10}{3}-3 \end{array}\right] = \left[\begin{array}{ccc} \frac{52}{3} & -\frac{5}{3} &-26\\ -\frac{8}{3} &6&- \frac{19}{3} \end{array}\right]](https://tex.z-dn.net/?f=%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-+%5Cfrac%7B2%7D%7B3%7D%2B18+%26amp%3B+%5Cfrac%7B4%7D%7B3%7D-3+%26amp%3B-2-24%5C%5C+-%5Cfrac%7B8%7D%7B3%7D%2B0+%26amp%3B0%2B6%26amp%3B-+%5Cfrac%7B10%7D%7B3%7D-3+%5Cend%7Barray%7D%5Cright%5D++%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D+%5Cfrac%7B52%7D%7B3%7D++%26amp%3B+-%5Cfrac%7B5%7D%7B3%7D+%26amp%3B-26%5C%5C+-%5Cfrac%7B8%7D%7B3%7D+%26amp%3B6%26amp%3B-+%5Cfrac%7B19%7D%7B3%7D+%5Cend%7Barray%7D%5Cright%5D "= \left[\begin{array}{ccc}- \frac{2}{3}+18 & \frac{4}{3}-3 &-2-24\\ -\frac{8}{3}+0 &0+6&- \frac{10}{3}-3 \end{array}\right] = \left[\begin{array}{ccc} \frac{52}{3} & -\frac{5}{3} &-26\\ -\frac{8}{3} &6&- \frac{19}{3} \end{array}\right]")
Façamos da seguinte forma:
Só de olhar já deu preguiça!
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