Question

Sabendo-se que log(x) base A = 2, logb(x) base B = 3 e logc(x) base C = 5, calcule: a)logAB(x) b)logABC(x) c)log ab/c (x)

Answer 1

log(x) base A = 2, logb(x) base B = 3 e logc(x) base C = 5, calcule:

a)logAB(x) =  logA + logB ==> 2+3 ==> 5 

b)logABC(x) =  logA + logB + log C ==> 2+3+5 ==> 10  

c)log ab/c (x) =  logA + logB - log C ==> 2+3-5 ==> 0