Question

Calcule
A- ⁴√1
B- ⁵√-32
C- ⁵√243

Answer 1

Vamos lá :

$\sqrt[4]{1} = 1 ~~~, pois ~~1.1.1.1 = 1^4 = 1$

$\sqrt[5]{-32} = \sqrt[5]{-32} \\ \\ 32|2 \\ 16|2 \\ 08|2 \\ 04|2 \\ 02|2 \\ 01~~~~~~~==\ \textgreater \ 2*2*2*2*2 = 2^5 \\ \\ = \sqrt[5]{-2^5} = - 2$

$\sqrt[5]{243} \\ \\ 243 |3 \\ 081|3 \\ 027|3 \\ 009|3 \\ 003|3 \\ 001 ~~~~~~==\ \textgreater \ 3*3*3*3*3 = 3^5 \\ \\ \sqrt[5]{243} = \sqrt[5]{3^5} = 3$

Espero ter ajudado !!