Question

Fatore o termo da fraçao alegebrica e depois,cancelo os fator comun: b²-49/14b³-98b²

Answer 1

$\dfrac{b^2 - 49}{14b^3 - 98b^2} \\ \\ \\ \dfrac{(b - 7).(b + 7)}{14b^2.(b- 7)} \\ \\ \\ \dfrac{(\not b - \not7).(b + 7)}{14b^2.(\not b- \not 7)} \\ \\ \\ =\ \textgreater \ \dfrac{b + 7}{14b^2}$