Question

resolva as adições a seguir :

a) 3 2 b) 1 1 1
- + - - + - + -
5 7 2 3 4

c) 2 a d) x 3
- + - - + -
3 b y 4

Answer 1

a)  mmc = 35
$\frac{3}{5} + \frac{2}{7} => \frac{21+10}{35} => \frac{31}{35}$

b) mmc = 12
$\frac{1}{2} + \frac{1}{3} + \frac{1}{4} => \frac{6+4+3}{12} => \frac{13}{12}$

c) mmc = 3b
$\frac{2}{3} + \frac{a}{b} => \frac{3a + 2b}{3b}$

d) mmc = 4y
$\frac{x}{y} + \frac{3}{4} => \frac{4x + 3y}{4y}$