Question

(x+1)²=4 me ajudemmm

Answer 1

(x+1)²=4
x²+x+x+1=4
x²+2x+1-4=0
x²+2x-3=0
a=1; b=2, c=-3

∆=b²-4ac⇒ ∆=2²-4.1.(-3)⇒ ∆=4+12⇒ ∆=16

x=-b±√∆ / 2.a⇒ x=-2± √16 / 2.1⇒ x=-2±4 / 2

x'=-2+4/2⇒ x'=2/2⇒ x'=1
x''=-2-4/2⇒ x''=-6/2⇒ x''= -3

S={-3 ; 1}

Answer 2

E aí brother,

basta fazer assim:

$(x+1) ^{2}=4\\ (x+1)= \sqrt{4}\\ (x+1)=\pm2\\\\ x+1=2~\to~x=2-1~\to~x'=1\\ x+1=-2~\to~x=-2-1~\to~x''=-3\\\\ \boxed{S=\{1,-3\}}$


Espero ter ajudado e tenha ótimos estudos =))