Respostas
respondido por:
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Boa noite!
Solução!
Para determinar o valor de x,tem que resolver o determinante da matriz.
![\begin{vmatrix}
2 & 4&1 \\
2 & 4&x \\
3&1&2
\end{vmatrix}=0\\\\\\
Determinante~~da~~matriz!\\\\\\\\\\\\
\begin{vmatrix}
2 & 4&1&2&4 \\
2 & 4&x&2&4 \\
3&1&2&3&1
\end{vmatrix}=0\\\\\\\\\
Vamos~~ multiplicar ~~as ~~diagonais~~ principais ~~e ~~secundarias.\\\\\\\
(16+12x+2)+(-12-2x-16)=0\\\\\\
(12x-2x+18-28)=0\\\\\
10x-10=0\\\\\ 10x=10\\\\\\
x= \dfrac{10}{10} \\\\\\
x=1\\\\\\\\\
\boxed{Resposta:~~x=1}](https://tex.z-dn.net/?f=%5Cbegin%7Bvmatrix%7D+%0A++2+%26amp%3B+4%26amp%3B1+%5C%5C+%0A++2+%26amp%3B+4%26amp%3Bx+%5C%5C%0A3%26amp%3B1%26amp%3B2%0A++%5Cend%7Bvmatrix%7D%3D0%5C%5C%5C%5C%5C%5C%0ADeterminante%7E%7Eda%7E%7Ematriz%21%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cbegin%7Bvmatrix%7D+%0A++2+%26amp%3B+4%26amp%3B1%26amp%3B2%26amp%3B4+%5C%5C+%0A++2+%26amp%3B+4%26amp%3Bx%26amp%3B2%26amp%3B4+%5C%5C%0A3%26amp%3B1%26amp%3B2%26amp%3B3%26amp%3B1%0A++%5Cend%7Bvmatrix%7D%3D0%5C%5C%5C%5C%5C%5C%5C%5C%5C%0AVamos%7E%7E+multiplicar+%7E%7Eas+%7E%7Ediagonais%7E%7E+principais+%7E%7Ee+%7E%7Esecundarias.%5C%5C%5C%5C%5C%5C%5C%0A%2816%2B12x%2B2%29%2B%28-12-2x-16%29%3D0%5C%5C%5C%5C%5C%5C%0A%2812x-2x%2B18-28%29%3D0%5C%5C%5C%5C%5C%0A10x-10%3D0%5C%5C%5C%5C%5C+10x%3D10%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B10%7D%7B10%7D+%5C%5C%5C%5C%5C%5C%0Ax%3D1%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A%7E%7Ex%3D1%7D%0A "\begin{vmatrix}
2 & 4&1 \\
2 & 4&x \\
3&1&2
\end{vmatrix}=0\\\\\\
Determinante~~da~~matriz!\\\\\\\\\\\\
\begin{vmatrix}
2 & 4&1&2&4 \\
2 & 4&x&2&4 \\
3&1&2&3&1
\end{vmatrix}=0\\\\\\\\\
Vamos~~ multiplicar ~~as ~~diagonais~~ principais ~~e ~~secundarias.\\\\\\\
(16+12x+2)+(-12-2x-16)=0\\\\\\
(12x-2x+18-28)=0\\\\\
10x-10=0\\\\\ 10x=10\\\\\\
x= \dfrac{10}{10} \\\\\\
x=1\\\\\\\\\
\boxed{Resposta:~~x=1}")
Boa noite!
Bons estudos!
Solução!
Para determinar o valor de x,tem que resolver o determinante da matriz.
Boa noite!
Bons estudos!
respondido por:
0
A solução está no anexo.
Anexos:
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