Question

Como resolve x²-2x=0 na formula de Bhaskara?

Answer 1

x² - 2x = 0

Δ = b² - 4ac = (-2)² - 4.1.0 = 4

X' = -b + √Δ / 2a = 2 + 2 / 2 = 4 / 2 = 2

X'' = -b - √Δ / 2a = 2 - 2 / 2 = 0 / 2 = 0