Question

determine a 14 termo da P.G (1536,768,384,192,...)?

Answer 1

a1 = 1536
q = 768/1536 = 1/2
n = 14
an = ?

an = a1 . q^(n-1)
an = 1536 . (1/2)^(14-1)
an = 1536 . (1/2)^13
an = 1536 . (1/8192)
an = 1536/8192            simplifica por 512 
an = 3/16