Question

quanto da o sistema xy-6=0
2x+3y = 12

Answer 1

xy-6=0       
2x+3y=12    3y=12-2x   Y=12-2x/3

x(12-2x/3)-6=0
12x-2x²-18=0
-2x²+12x-18=0 

Δ=12²-4.(-2).(-18)
Δ= 144-144
Δ=0  

X=-b/2a
X=-12/2.(-2)
X=-12/-4
X=3

Y=12-2.3/3
Y=12-6/3
Y=6/3 
Y=2

Resposta: 

X=3 Y= 2