Question

A)3 raiz quadrada 3=27^x
B)3^x-3^2-x=8

Answer 1

E aí Carlos,

use as propriedades da potenciação:

$3 \sqrt{3}=27 ^{x}\\ \sqrt{3 ^{2}*3 }=(3^{3})^{x}\\ \sqrt{3 ^{3} }=3 ^{3x}\\ \not3 ^{ \frac{3}{2} }=\not3 ^{3x}\\ \frac{3}{2}=3x\\ x=1/2\\\\ S=\{ \frac{1}{2}\}$

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$3 ^{x}-3 ^{2-x}=8\\ 3 ^{x}- \frac{3 ^{2} }{3 ^{x} }=8\\\\ 3 ^{x}=y\\\\ y- \frac{9}{y}=8\\\\ (y*y)-9=8*y\\ y ^{2}-9=8y\\ y ^{2}-8y-9=0\\\\ y'=-1~~~~y''=9\\\\ ~~~~~~~~~~~~~~~~~~~~~~~~3 ^{x}=y:\\\\ 3 ^{x}=-1~~nao~serve~~~~~~~~~~~~~~~3 ^{x}=9\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\not3 ^{x}=\not3 ^{2}\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~x=2\\\\ S=\{2\}$

Esperto ter ajudado e tenha ótimos estudos =))