Question

f(x)=x2+10×+25 efetue os zero da função quadratica

Answer 1

f(x)=x²+10x +25 -> basta igualar a zero
x²+10x+ 25=0
D= b²-4ac -> D= delta
D= (10 )²- 4 .1 . 25
D= 100 - 100
D= 0
 x= -b+/- VD/2a   -> VD= raiz de delta
 x= -10 +/- V0/2
 x= -10 +/- 0 /2
 x'= -10 + 0/2
 x'= -10/2 = -5
x''= -10 -0/2
x''= -10 /2 = -5
S= { -5 }