Question

análise as equações do segundo grau e determine as suas raízes a) 3x ²-8x=0

Answer 1

3 x² - 8 x = 0
x(3 x - 8 ) = 0
x = 0
3 x - 8 = 0
3 x = 8
x = 8/3
S = {0, 8/3}

Answer 2

$3 x^{2} -8x = 0$

Δ = $b^{2} -4ac$
Δ = $(-8)^{2} -4.3.0$
Δ = 64

x' = $\frac{-b+ \sqrt{64} }{2a}$

x' = $\frac{8+8}{2.3} = \frac{16}{6} = \frac{8}{3}$

x'' = $\frac{-b- \sqrt{64} }{2a}$

x'' = $\frac{8-8}{6} = \frac{0}{6} = 0$