me ajudem por favor nesse exercicio :Escreva a equacao geral da reta que passa pelos pontos indicados. Determine um ponto C que esteja na reta:B)A(5,2) e D(-1-6)
Respostas
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Boa noite!
Solução!
![A(5,2)\\\\
D(-1,-6)\\\\\\
1\º)~~Determinar~~o~~coeficiente~~angular~~que~~sera~~indicado\\\\por~~m\\\\\\
m= \dfrac{yD-yA}{xD-xA}\\\\\\\
m= \dfrac{-6-2}{-1-5}\\\\\\\
m= \dfrac{-8}{-6}\\\\\\\
\boxed{m= \dfrac{8}{6}}](https://tex.z-dn.net/?f=A%285%2C2%29%5C%5C%5C%5C%0AD%28-1%2C-6%29%5C%5C%5C%5C%5C%5C%0A1%5C%C2%BA%29%7E%7EDeterminar%7E%7Eo%7E%7Ecoeficiente%7E%7Eangular%7E%7Eque%7E%7Esera%7E%7Eindicado%5C%5C%5C%5Cpor%7E%7Em%5C%5C%5C%5C%5C%5C%0Am%3D+%5Cdfrac%7ByD-yA%7D%7BxD-xA%7D%5C%5C%5C%5C%5C%5C%5C%0Am%3D+%5Cdfrac%7B-6-2%7D%7B-1-5%7D%5C%5C%5C%5C%5C%5C%5C+%0Am%3D+%5Cdfrac%7B-8%7D%7B-6%7D%5C%5C%5C%5C%5C%5C%5C%0A%0A%5Cboxed%7Bm%3D+%5Cdfrac%7B8%7D%7B6%7D%7D%0A+ "A(5,2)\\\\
D(-1,-6)\\\\\\
1\º)~~Determinar~~o~~coeficiente~~angular~~que~~sera~~indicado\\\\por~~m\\\\\\
m= \dfrac{yD-yA}{xD-xA}\\\\\\\
m= \dfrac{-6-2}{-1-5}\\\\\\\
m= \dfrac{-8}{-6}\\\\\\\
\boxed{m= \dfrac{8}{6}}")
Equação da reta!
![A(5,2)\\\\\\
m= \dfrac{8}{6}\\\\\\\\
y-yA=m(x-xA)\\\\\
y-2= \dfrac{8}{6}(x-5)\\\\\\\
y-2= \dfrac{8x-40}{6}\\\\\\\
6y-12=8x-40\\\\\
-8x+6y-12+40=0.(-1)\\\\\\
\boxed{8x-6y-28=0}~~Eq~~da~~reta~~na~~forma~~geral.](https://tex.z-dn.net/?f=A%285%2C2%29%5C%5C%5C%5C%5C%5C%0Am%3D+%5Cdfrac%7B8%7D%7B6%7D%5C%5C%5C%5C%5C%5C%5C%5C%0Ay-yA%3Dm%28x-xA%29%5C%5C%5C%5C%5C%0Ay-2%3D+%5Cdfrac%7B8%7D%7B6%7D%28x-5%29%5C%5C%5C%5C%5C%5C%5C+%0Ay-2%3D+%5Cdfrac%7B8x-40%7D%7B6%7D%5C%5C%5C%5C%5C%5C%5C%0A6y-12%3D8x-40%5C%5C%5C%5C%5C%0A-8x%2B6y-12%2B40%3D0.%28-1%29%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7B8x-6y-28%3D0%7D%7E%7EEq%7E%7Eda%7E%7Ereta%7E%7Ena%7E%7Eforma%7E%7Egeral.+%0A%0A%0A "A(5,2)\\\\\\
m= \dfrac{8}{6}\\\\\\\\
y-yA=m(x-xA)\\\\\
y-2= \dfrac{8}{6}(x-5)\\\\\\\
y-2= \dfrac{8x-40}{6}\\\\\\\
6y-12=8x-40\\\\\
-8x+6y-12+40=0.(-1)\\\\\\
\boxed{8x-6y-28=0}~~Eq~~da~~reta~~na~~forma~~geral.")
Ponto C pertencente a reta!
![C(x,y)\\\\\\
8x-6y-28=0\\\\\
8(2)-6(-2)-28=0\\\\\
16+12-28=0\\\\\
28-28=0\\\\\
0=0\\\\\
C(2,-2)](https://tex.z-dn.net/?f=C%28x%2Cy%29%5C%5C%5C%5C%5C%5C%0A%0A8x-6y-28%3D0%5C%5C%5C%5C%5C%0A8%282%29-6%28-2%29-28%3D0%5C%5C%5C%5C%5C%0A16%2B12-28%3D0%5C%5C%5C%5C%5C%0A28-28%3D0%5C%5C%5C%5C%5C%0A0%3D0%5C%5C%5C%5C%5C%0AC%282%2C-2%29%0A%0A "C(x,y)\\\\\\
8x-6y-28=0\\\\\
8(2)-6(-2)-28=0\\\\\
16+12-28=0\\\\\
28-28=0\\\\\
0=0\\\\\
C(2,-2)")
Boa noite!
Bons estudos!
Solução!
Equação da reta!
Ponto C pertencente a reta!
Boa noite!
Bons estudos!
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