Question

Sabendo q log2=0,301 e log3=0,477 determine o valor d log162

Answer 1

$log\ 162 = log\ 2*3^4\\\\ log\ 162 = log\ 2+4\ log\ 3\\\\ log\ 162 = 0,301+4(0,477)\\\\ log\ 162 = 0,301+1,908\\\\\ \boxed{log\ 162 = 2,209}$