Question

Resolva as seguintes equaçõesA)-3x+18=0B) x-3 (4-x)=7x-(1-x)C) x/2+1/3=3x/5-2/5D) 13(2x-3)-5(2-x)=5(-3+6x)

Answer 1

A)-3x+18=0
-3x=-18
x=-18÷-3
x=6

B) x-3 (4-x)=7x-(1-x)
x-3x(4-x)=7x-1+x
x-3x(4-x)=8x-1
x-(3x4-3xx)=8x-1
x-(12-3x)=8x-1
x-12+3x=8x-1
4x-12=8x-1
4x-8x=-1+12
-4x=11
x=11÷-4
x=$\frac{11}{-4}$
x=$- \frac{11}{4}$
x=-2.75

C) x/2+1/3=3x/5-2/5
$\frac{1}{2}x- \frac{3}{5}x=- \frac{2}{5}- \frac{1}{3}$
$\frac{5x1-2x3}{10}x= -\frac{2}{5}- \frac{1}{3}$
$\frac{5-6}{10}x=- \frac{2}{5}- \frac{1}{3}$
$- \frac{1}{10}x=- \frac{2}{5}- \frac{1}{3}$
$- \frac{1}{10}x= \frac{3x-2-5x1}{15}$
$- \frac{1}{10}x= \frac{3x-2-5}{15}$
$- \frac{1}{10}x= \frac{-6-5}{15}$
$- \frac{1}{10}x=- \frac{-11}{15}$
x=-$\frac{11}{15 }÷(- \frac{1}{10} )$
x=-$\frac{11}{15}x(- \frac{10}{1} )$
x=-$\frac{11}{15}x-10$
x=-$\frac{11}{3}x-2$
x=$\frac{11}{3}x-2$
x=$\frac{11x2}{3}$
x=$\frac{22}{3}$

D) 13(2x-3)-5(2-x)=5(-3+6x)
13x2x-13x3-5x(2-x)=5x(-3+6x)
26x-39-5x((2-x)=5x(-3+6x)
26x-39-(5x2-5xx)=5x(-3+6x)
26x-39-(10-5x)=5x(-3+6x)
26x-39-10+5x=5x(-3+6x)
31x-39-10=5x(-3+6x)
31x-49=5x(-3+6x)
31x-49=5x-3+5x6x
31x-49=+15+5x6x
31x-49=-15+30x
31x-30x=-15+49
x=-15+49
x=34