Question

A área entre as retas x= -π/3, x=π/3, y=1 e a curva y(x) = 3cos(3x) é:
Escolha uma:
a. 0,33 u.a.
b. 0 u.a.
c. 2,45 u.a.
d. 3,18 u.a.
e. 1,37 u.a.

Answer 1

Oi Fisaque

x = -π/3, x = π/3 , y = 1

f(x) = 3cos(3x) 

F(x) = ∫ 3cos(3x) dx = sen(3x) + C

F(-π/3) = 0
F(π/3) = 0

área

A = F(π/3) - F(-π/3) = 0 - 0 = 0 u.a Oi Fisaque

x = -π/3, x = π/3 , y = 1

f(x) = 3cos(3x) 

F(x) = ∫ 3cos(3x) dx = sen(3x) + C

F(-π/3) = 0
F(π/3) = 0

área

A = F(π/3) - F(-π/3) = 0 - 0 = 0 u.a (alternativa B)

Answer 2

resposta correta 1,37 u.a conforme AVA