• Matéria: Matemática
  • Autor: daisyfortunarib
  • Perguntado 9 anos atrás

(n+2)!+(n+1)(n-1)! / (n+1)(n-1)

Respostas

respondido por: MATHSPHIS
2
\frac{(n+2)!+(n+1)(n-1)! }{ (n+1)(n-1)}=\frac{(n+2)!}{(n+1)(n-1)}+\frac{(n+1)(n-1)!}{(n+1)(n-1)}=\\
\\
\frac{(n+2)(n+1)n!}{(n+1)(n-1)}+\frac{(n+2)(n+1)n!}{(n+1)(n-1)}=\frac{(n+2)n!}{n-1}+\frac{(n+2)n!}{n-1}=\\
\\
\boxed{\frac{2(n+2)n!}{n-1}}
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