Question

Dadas as funções F(x)= -x*ao quadrado* +2x+3 e -> g(x) = x*ao quadrado* -2x-3, calcule:
a) f(3)=
b) f(-2)=
c) f(10)=
d) f (-0,2)=
e) g(1)=
f) g(-4)=
g) g(0)=
h) g(1/2)=

Answer 1

f(3) = -3 + 2(3) + 3
f(3) = 18

f(-2) = (-2)² + 2 (-2) + 3
f(-2) = 3

f(10) = (-10)² + 2(10) + 3
f(10) = 123

f(-0,2) = (-0,2)² + 2(-0,2) + 3
f(-0,2) = 2,64

g(1) = 1² - 2(1) - 3
g(1) = -4

g(-4) = (-4)² -2(-4) - 3
g(-4) = 21

g(0) = 0² - 2(0) - 3
g(0) = -3

g(1/2) = (1/2)² - 2(1/2) -3
g(1/2) = -15/4