Question

preciso encontra a fraça geratriz de cada dizima periodica ex:12,488...

Answer 1

12,488...  = 1248 -12  = 1236 

                         99                 99

 

 

 

Answer 2

Olá Eduardo.

 

$<var>12,488...=12,4+0,0888...=\frac{124}{10}+\frac{0,888...}{10} =</var>$

 

$=\frac{62}{5} + \frac{1}{10} \times \frac89=\frac{62}{5} + \frac{8}{90} =$

 

$=\frac{1116+8}{90}=\frac{1124}{90}=\frac{562}{45}$