Question

Sendo f(x)= x²-2x+3 obtenha f(-2), f(0), f(1) e f(2+k)?

Answer 1

f(-2)=(-2)²-2.(-2)+3
f(-2)=4+4+3
f(-2)=11

f(0)=0²-2.0+3
f(0)=3

f(1)=1²-2.1+3
f(1)=-1+3
f(1)=2

f(2+k)=(2+k)²-2.(2+k)+3
f(2+k)=4+4k+k²-4-2k+3
f(2+k)=k²+2k+3