Question

Se ㏒ₐb = 3 , ㏒ₐc = 4 e ㏒ₐb/c = x, pode-se afirmar que:
a) a = b/c
b) a = c/b
c) a = -c/b
d) a= - b/c
e) a = 1

Answer 1

Oi Barbara

loga(b) = 3
loga(c) = 4 

loga(b/c) = loga(b) - loga(c) = 3 - 4 = -1

log(b/c) = -log(a) = log(1/a)

b/c = 1/a 

a = c/b (B) 

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