Question

Dada a função f (x) = 2x² + 3x+1. Calcule:

A) f (-1)
B) f (1/3)
C) f (0)
D) f (2)

Answer 1

A) f(-1)=2(-1)²+3(-1)+1 
=2(1)-3+1
=2-3+1
=0

B) f(1/3)=2(1/3)²+3(1/3)+1
=2(1/9)+(3/3)+1
=$\frac{2}{9}$+1+1
=$\frac{2+18}{9} = \frac{20}{9}$

C) f(0)=0+0+1
=1

D) f(2)=2(2)²+3(2)+1
=2(4)+6+1
=8+7
=15