Question

Dados z1= 2 (cos π/12 + isen /12) e z2 = 3 (cos π/4 +i sen π/4_ então z1 * z2 é:

Answer 1

6[cos (π/12 + π/4) +  isen (π/12 + π/4)]  
6[cos (4π/12) +  isen (4π/12)]  
6[cos (π/3) +  isen (π/3)]                  
6[1/2 +  i√3/2]                      
Resp:3 + i3√3