Question

2. Dada f(x)= x² - 3x + 1 . Encontre:
f(2 + h)-f (2)
    h

Answer 1

f(2+h) = (2+h)^2 - 3(2+h) +1 = 4+4h+h^2 -6-3h +1 = h^2+h-1

f(2) = 2^2 - 3(2) + 1 = -1

assim: [H^2 +h -1 -(-1)]/h

h(h+1)/h = h+1 

confere?

Answer 2

Olá, Vando.

$\frac{f(2 + h)-f (2)}h=\frac{(2+h)^2-3(2+h)+1-2^2+3\cdot2-1}h=\\=\frac{4+4h+h^2-6-3h-4+6}h=\frac{h^2+h}h=\frac{h(h+1)}h=h+1$