Question

 Se x²+y²=1681 e x.y=360, calcule x+y, sabendo que x e y são números positivos:

Answer 1

$(x+y)^2=(x^2+y^2)+2(xy)=1681+2.360=1681+720=2401\\ \\ x+y= \sqrt{2401}= 49$

Answer 2

$y ^{2}$=129600
129600-1681=127919
$x^{2} =$=127919
127919+129600=257519