• Matéria: Matemática
  • Autor: anaAnnafloreengeli
  • Perguntado 8 anos atrás

lim 9-x/√x-3 quando x tende a 9

Respostas

respondido por: DanJR
25
Olá Ana!

\\ \mathsf{\lim_{x \to 9} \frac{9 - x}{\sqrt{x} - 3} =} \\\\\\ \mathsf{\lim_{x \to 9} \frac{9 - x}{\sqrt{x} - 3} \cdot \frac{\sqrt{x} + 3}{\sqrt{x} + 3} =} \\\\\\ \mathsf{\lim_{x \to 9} \frac{(9 - x)(\sqrt{x} + 3)}{x - 9} =} \\\\\\ \mathsf{\lim_{x \to 9} \frac{(9 - x)(\sqrt{x} + 3)}{- (9 - x)} =} \\\\\\ \mathsf{\lim_{x \to 9} \frac{(\sqrt{x} + 3)}{- 1} =}

\\ \mathsf{\lim_{x \to 9} \frac{(\sqrt{x} + 3)}{- 1} =} \\\\\\ \mathsf{\lim_{x \to 9} - (\sqrt{x} + 3) =} \\\\\\ \mathsf{- (\sqrt{9} + 3) =} \\\\ \mathsf{- 3 - 3 =} \\\\ \boxed{\boxed{\mathsf{- 6}}}
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